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If the HCF of two numbers is (35), their LCM is (1470), and one number is (210), what is the other number?

Answer and explanation

Correct answer: (245)

Step 1: Product of two numbers (=) HCF (\times) LCM. Step 2: The other number is (\frac{35\times1470}{210}=245). Step 3: Divide first to keep the calculation simple.

Related tags

Real-NumbersHcf-LcmUnknown-NumberHcf And Lcm Using Prime FactorisationHcf Lcm Using Prime FactorisationReal NumbersMathematicsClass 10 Mcq

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