If the AP is (4,9,14,19,\ldots), what is the (16)th term?
Answer and explanation
Correct answer: \(79\)
Here, the first term is \(a=4\) and the common difference is \(d=9-4=5\). The \(n\)th term of an AP is \(a_n=a+(n-1)d\). Therefore, \(a_{16}=4+(16-1)\times5=4+75=79\). Hence, \(79\) is correct. \(81\) would be obtained for the \(17\)th term, not the \(16\)th term. Exam tip: always use \(n-1\) in the formula for the \(n\)th term.
Frequently asked questions
What is the correct answer to this question?
\(79\)
Why is this the correct answer?
Here, the first term is \(a=4\) and the common difference is \(d=9-4=5\). The \(n\)th term of an AP is \(a_n=a+(n-1)d\). Therefore, \(a_{16}=4+(16-1)\times5=4+75=79\). Hence, \(79\) is correct. \(81\) would be obtained for the \(17\)th term, not the \(16\)th term. Exam tip: always use \(n-1\) in the formula for the \(n\)th term.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.
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