Update

Muft Shiksha™ एक 100% Free Education Portal है 🇮🇳, जिसका उद्देश्य Class 9–12 के हर विद्यार्थी तक High-Quality Education को पूरी तरह मुफ्त पहुँचाना है। 🇮🇳 हम मानते हैं कि अच्छी शिक्षा किसी student की आर्थिक स्थिति पर निर्भर नहीं होनी चाहिए। 🇮🇳 हर विद्यार्थी को वही Quality Study Material, MCQs, Quizzes, Exam Preparation, Concept-Based Learning और Bilingual Support मिलना चाहिए, जो आमतौर पर महंगी Coaching या Premium Platforms में मिलता है। Muft Shiksha™ 🇮🇳 इसी सोच के साथ बनाया गया है

Subjects
0 reads0 ratings0 helpful

If terms are defined by A_n=4n−9, what does A_15−A_14 represent?

Advertisement

Answer and explanation

Correct answer: Common difference

First calculate the two consecutive terms from the given rule. A_15=4(15)−9=60−9=51, while A_14=4(14)−9=56−9=47. Hence A_15−A_14=51−47=4. More generally, substituting n+1 and n gives A_{n+1}−A_n=[4(n+1)−9]−[4n−9]=4, a constant independent of n. The difference between consecutive terms of an arithmetic progression is its common difference, so option B is correct. It is not the first term, the number of terms, or a last term.

Related tags

Arithmetic ProgressionCommon DifferenceNth-Term ExpressionSequence RuleIntroduction To Aps And Common Difference.Introduction To Aps And Common DifferenceArithmetic Progressions (Ap)Arithmetic Progressions Ap

Frequently asked questions

What is the correct answer to this question?

Common difference

Why is this the correct answer?

First calculate the two consecutive terms from the given rule. A_15=4(15)−9=60−9=51, while A_14=4(14)−9=56−9=47. Hence A_15−A_14=51−47=4. More generally, substituting n+1 and n gives A_{n+1}−A_n=[4(n+1)−9]−[4n−9]=4, a constant independent of n. The difference between consecutive terms of an arithmetic progression is its common difference, so option B is correct. It is not the first term, the number of terms, or a last term.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Introduction to APs and common difference..

Was this question useful?

No ratings yetWrite a review / Rate this question

Student Reviews

No published reviews yet.

Advertisement