0 reads0 ratings0 helpful
If roots of (x^2-14x+33=0) are (\alpha,\beta), which equation has roots (\alpha+5,\beta+5)?
Advertisement
Answer and explanation
Correct answer: (x^2-24x+128=0)
The roots are (3,11), so new roots are (8,16), and the equation is ((x-8)(x-16)=0). In exams, form the new roots and then the new equation.
Frequently asked questions
What is the correct answer to this question?
(x^2-24x+128=0)
Why is this the correct answer?
The roots are (3,11), so new roots are (8,16), and the equation is ((x-8)(x-16)=0). In exams, form the new roots and then the new equation.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement