If one root of (x^2+px+64=0) is double the other and both are negative, what is (p)?

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Answer and explanation

Correct answer: (12\sqrt{2})

Let the roots be (-r) and (-2r), then (2r^2=64) gives (r=4\sqrt{2}), and (p=3r=12\sqrt{2}). In exams, keep signs of both roots carefully.

What is the correct answer to this question?

(12\sqrt{2})

Why is this the correct answer?

Let the roots be (-r) and (-2r), then (2r^2=64) gives (r=4\sqrt{2}), and (p=3r=12\sqrt{2}). In exams, keep signs of both roots carefully.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.

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