If (n=14q+13), what is the remainder when (n^2+2n+1) is divided by 14?
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Answer and explanation
Correct answer: 0
Step 1: (n^2+2n+1=(n+1)^2). Step 2: Since the remainder of (n) is 13, the remainder of (n+1) is 0. Step 3: When (n+1) is divisible by 14, its square is also divisible by 14.
Frequently asked questions
What is the correct answer to this question?
0
Why is this the correct answer?
Step 1: (n^2+2n+1=(n+1)^2). Step 2: Since the remainder of (n) is 13, the remainder of (n+1) is 0. Step 3: When (n+1) is divisible by 14, its square is also divisible by 14.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Euclid’s Division Lemma.
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