If in an AP (a_9=44) and (a_{21}=116), what is the value of (a_{38})?
Answer and explanation
Correct answer: (218)
(d=\frac{116-44}{21-9}=6), so (a_{38}=116+17\times6=218). First find (d), then move forward from the nearer term.
Frequently asked questions
What is the correct answer to this question?
(218)
Why is this the correct answer?
(d=\frac{116-44}{21-9}=6), so (a_{38}=116+17\times6=218). First find (d), then move forward from the nearer term.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.