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If \(\alpha,\beta\) are roots of \(7x^2-25x+12=0\), what is \((\alpha-\beta)^2\)?
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Answer and explanation
Correct answer: \( \frac{289}{49}\) / \(\frac{289}{49}\)
\((\alpha-\beta)^2=(\alpha+\beta)^2-4\alpha\beta=\left(\frac{25}{7}\right)^2-\frac{48}{7}=\frac{289}{49}\). In exams, convert fractions to a common denominator.
Frequently asked questions
What is the correct answer to this question?
\( \frac{289}{49}\) / \(\frac{289}{49}\)
Why is this the correct answer?
\((\alpha-\beta)^2=(\alpha+\beta)^2-4\alpha\beta=\left(\frac{25}{7}\right)^2-\frac{48}{7}=\frac{289}{49}\). In exams, convert fractions to a common denominator.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
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