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If a number is divisible by both (2^5\times3^2\times7) and (2^3\times3^5\times11), what will be the power of (3) in the smallest such number?

Answer and explanation

Correct answer: (5)

Step 1: The smallest such number is the LCM of the two given numbers. Step 2: The powers of (3) are (2) and (5), so the higher power (5) will be used. Step 3: For divisibility, choose the higher power.

Related tags

Real-NumbersLcmPrime-PowerHcf And Lcm Using Prime FactorisationHcf Lcm Using Prime FactorisationReal NumbersMathematicsClass 10 Mcq

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