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Class 10MathematicsReal NumbersEuclid’s Division LemmaExpertLevel 2
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If a number gives quotient 31 and remainder 95 when divided by 96, what is the number?

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Answer and explanation

Correct answer: 3071

Step 1: Number (=) divisor (\times) quotient (+) remainder. Step 2: (96\times31+95=2976+95=3071). Step 3: The remainder 95 is less than divisor 96, so the form is valid.

Related tags

Euclids-Division-LemmaConstruct-NumberQuotient-Remainder

Frequently asked questions

What is the correct answer to this question?

3071

Why is this the correct answer?

Step 1: Number (=) divisor (\times) quotient (+) remainder. Step 2: (96\times31+95=2976+95=3071). Step 3: The remainder 95 is less than divisor 96, so the form is valid.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Euclid’s Division Lemma.

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10 more MCQs
  1. 1In Euclid’s Division Lemma, if (a) and (b) are positive integers, which condition is correct for the remainder (r)?
  2. 2If (35=6q+r) and (0 \le r < 6), what are the values of (q) and (r)?
  3. 3Which is the standard form of Euclid’s Division Lemma?
  4. 4If a number leaves remainder (0) when divided by (9), in which form can it be written?
  5. 5What possible remainders can occur when an integer is divided by (5)?
  6. 6What is the remainder when (52) is divided by (7)?
  7. 7Which condition is necessary for (b) in Euclid’s Division Lemma?
  8. 8If (a=17) and (b=4), which is the correct Euclidean form (a=bq+r)?
  9. 9How many possible remainders are there when a number is divided by (3)?
  10. 10If a number is odd, what remainder will it leave when divided by (2)?
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