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If the nth term of an AP is aₙ = 13n − 6, what is the value of a₁₈ − a₁₁?यदि किसी AP का nवाँ पद aₙ = 13n − 6 है, तो a₁₈ − a₁₁ का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 9191
The common difference is 13. The 18th and 11th terms are 7 positions apart, so a₁₈ − a₁₁ = 7 × 13 = 91.सार्व अंतर 13 है। 18वाँ और 11वाँ पद स्थानों में 7 पद दूर हैं, इसलिए a₁₈ − a₁₁ = 7 × 13 = 91।
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