If (a_6=31) and (a_{14}=79), what is the common difference of the AP?
Answer and explanation
Correct answer: 6
For an AP, \(a_{14}-a_6=(14-6)d\). Thus, \(79-31=8d\), so \(48=8d\) and \(d=6\). If the common difference were 4, the difference over 8 positions would be only 32, not the given 48. Exam tip: when two non-consecutive terms are given, divide the difference of the terms by the difference of their indices.
Frequently asked questions
What is the correct answer to this question?
6
Why is this the correct answer?
For an AP, \(a_{14}-a_6=(14-6)d\). Thus, \(79-31=8d\), so \(48=8d\) and \(d=6\). If the common difference were 4, the difference over 8 positions would be only 32, not the given 48. Exam tip: when two non-consecutive terms are given, divide the difference of the terms by the difference of their indices.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.