If \(a_1=3\), \(a_{2n+1}=123\), and \(d=4\), what is the value of (n)?
Answer and explanation
Correct answer: (15)
From \(123=3+2n\cdot4\), \(120=8n\), so \(n=15\). In index (2n+1), subtract (1) to get the multiplier.
Frequently asked questions
What is the correct answer to this question?
(15)
Why is this the correct answer?
From \(123=3+2n\cdot4\), \(120=8n\), so \(n=15\). In index (2n+1), subtract (1) to get the multiplier.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.