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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationHard
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If (96), (144), and (192) are to be divided into the maximum number of equal parts, what will be the number of parts?

Answer and explanation

Correct answer: (48)

Step 1: The maximum number of equal parts is found using HCF. Step 2: (96=2^5\times3), (144=2^4\times3^2), and (192=2^6\times3), so HCF (=2^4\times3=48). Step 3: For maximum equal division, use HCF.

Related tags

Real-NumbersHcfEqual-PartsHcf And Lcm Using Prime FactorisationHcf Lcm Using Prime FactorisationReal NumbersMathematicsClass 10 Mcq
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10 more MCQs
  1. 1If the product of two numbers is 3780 and their LCM is 315, what is their HCF?
  2. 2What is the HCF of (18) and (24) using prime factorisation?
  3. 3What is the LCM of (18) and (24) using prime factorisation?
  4. 4What is the HCF of (40) and (60)?
  5. 5What is the LCM of (40) and (60)?
  6. 6What will be the HCF of (45) and (75)?
  7. 7What will be the LCM of (45) and (75)?
  8. 8Which is the HCF of (32) and (48)?
  9. 9Which is the LCM of (32) and (48)?
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