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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationHard
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If (96), (128), and (160) are to be divided into the maximum equal parts, what will be the number of parts?

Answer and explanation

Correct answer: (32)

Step 1: The maximum number of equal parts is found by HCF. Step 2: (96=2^5\times3), (128=2^7), and (160=2^5\times5), so HCF (=2^5=32). Step 3: For maximum equal division, use HCF.

Related tags

Real-NumbersHcfEqual-PartsHcf And Lcm Using Prime FactorisationHcf Lcm Using Prime FactorisationReal NumbersMathematicsClass 10 Mcq
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