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For (\frac{1}{x}+x=\frac{50}{7}), (x\neq0), what quadratic form is obtained?(\frac{1}{x}+x=\frac{50}{7}), (x\neq0), को द्विघात रूप में बदलने पर क्या मिलेगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (7x^2-50x+7=0)(7x^2-50x+7=0)
Multiplying both sides by (7x) gives (7+7x^2=50x), that is (7x^2-50x+7=0). In exams, remember the condition (x\neq0).दोनों पक्षों को (7x) से गुणा करने पर (7+7x^2=50x), यानी (7x^2-50x+7=0) मिलता है। परीक्षा में (x\neq0) शर्त याद रखें।
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