For (\frac{1}{x}+x=\frac{37}{6}), (x\neq0), what quadratic form is obtained?
Answer and explanation
Correct answer: (6x^2-37x+6=0)
Multiplying both sides by (6x) gives (6+6x^2=37x), that is (6x^2-37x+6=0). In exams, remember the condition (x\neq0).
Frequently asked questions
What is the correct answer to this question?
(6x^2-37x+6=0)
Why is this the correct answer?
Multiplying both sides by (6x) gives (6+6x^2=37x), that is (6x^2-37x+6=0). In exams, remember the condition (x\neq0).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Quadratic Equations. Topic: Methods of Solving Quadratic Equations.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.