0 reads0 ratings0 helpful
A student says that the sequence 15, 11, 7, 3, ldots is not an arithmetic progression because its terms are decreasing. What is the correct evaluation of this statement?एक छात्र कहता है कि श्रेणी 15, 11, 7, 3, ldots अंकगणितीय श्रेणी नहीं है क्योंकि इसके पद घट रहे हैं। इस कथन का सही मूल्यांकन क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: It is an AP because each consecutive difference is (-4 ).यह AP है, क्योंकि प्रत्येक क्रमागत अंतर (-4 ) है।
This is an AP since 11−15=−4, 7−11=−4, and 3−7=−4. A negative common difference makes terms decrease but does not stop it from being an AP. Exam tip: compare consecutive differences.यह AP है क्योंकि 11−15=−4, 7−11=−4 और 3−7=−4। सार्वांतर ऋणात्मक होने पर पद घटते हैं, पर AP बनी रहती है। परीक्षा में क्रमागत पदों का अंतर जाँचें।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
