A shopkeeper saves (15) rupees more than the previous day. If he saved (50) rupees on the first day, what will be the savings sequence?
Answer and explanation
Correct answer: \((50,65,80,95,\ldots)\)
The saving on the first day is the first term, so \(a=50\). The saving increases by \(15\) rupees each day, so the common difference is \(d=15\). Thus the terms are \(50, 50+15=65, 65+15=80, 80+15=95\), giving \((50,65,80,95,\ldots)\). Option D has a difference of \(15\), but it starts with \(65\), not \(50\). Exam tip: In an AP, always check both the first term and the difference between consecutive terms.
Frequently asked questions
What is the correct answer to this question?
\((50,65,80,95,\ldots)\)
Why is this the correct answer?
The saving on the first day is the first term, so \(a=50\). The saving increases by \(15\) rupees each day, so the common difference is \(d=15\). Thus the terms are \(50, 50+15=65, 65+15=80, 80+15=95\), giving \((50,65,80,95,\ldots)\). Option D has a difference of \(15\), but it starts with \(65\), not \(50\). Exam tip: In an AP, always check both the first term and the difference between consecutive terms.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Introduction to APs and common difference..
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
