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A number is divisible by both (2^5\times3^2\times11) and (2^3\times3^4\times5). What will be the power of (3) in the smallest such number?

Answer and explanation

Correct answer: (4)

Step 1: The smallest such number is the LCM of the two given numbers. Step 2: The powers of (3) are (2) and (4), so the higher power (4) is used. Step 3: For divisibility, choose the higher power.

Related tags

Real-NumbersLcmPrime-PowerHcf And Lcm Using Prime FactorisationHcf Lcm Using Prime FactorisationReal NumbersMathematicsClass 10 Mcq

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