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अभाज्य गुणनखंडन द्वारा महत्तम समापवर्तक और लघुत्तम समापवर्त्य
In this Class 10 Mathematics topic from Real Numbers, students learn to find the HCF and LCM of two or more numbers through prime factorisation. They break each number into prime factors, compare the resulting powers, and select the appropriate common factors: the lowest powers for HCF and the highest powers for LCM. The topic also develops accuracy in writing factor trees, simplifies comparison between methods, and helps students apply these concepts to numerical and everyday problem-solving situations.
TOPIC PRACTICE
Quiz this set
Up to 20 questions from this page. Select your focus, then start.
Which statement about HCF and LCM is correct for two numbers?
Correct answer: B
Step 1: For two numbers, a special relation is used. Step 2: The product of HCF and LCM equals the product of the two numbers. Step 3: Apply this relation directly only for two numbers.
Step 1: (30=2\times3\times5) and (42=2\times3\times7). Step 2: Take (2), (3), (5), and (7) with highest powers. Step 3: (2\times3\times5\times7=210), so the LCM is (210).
Step 1: (56=2^3\times7) and (84=2^2\times3\times7). Step 2: The smaller powers of common factors are (2^2) and (7). Step 3: (4\times7=28), so the HCF is (28).
Step 1: (56=2^3\times7) and (84=2^2\times3\times7). Step 2: The highest powers are (2^3), (3), and (7). Step 3: (8\times3\times7=168), so the answer is (168).
Step 1: (24=2^3\times3), (36=2^2\times3^2), and (48=2^4\times3). Step 2: The common smaller powers are (2^2) and (3). Step 3: (4\times3=12), so the HCF is (12).
Step 1: (24=2^3\times3), (36=2^2\times3^2), and (48=2^4\times3). Step 2: The highest powers are (2^4) and (3^2). Step 3: (16\times9=144), so the LCM is (144).
Step 1: (20=2^2\times5), (50=2\times5^2), and (70=2\times5\times7). Step 2: The common factors in all three are (2) and (5). Step 3: (2\times5=10), so the HCF is (10).
Step 1: (20=2^2\times5), (50=2\times5^2), and (70=2\times5\times7). Step 2: The highest powers are (2^2), (5^2), and (7). Step 3: (4\times25\times7=700), so the answer is (700).
Step 1: (42=2\times3\times7), (63=3^2\times7), and (105=3\times5\times7). Step 2: The common prime factors are (3) and (7). Step 3: (3\times7=21), so the answer is (21).
Step 1: (42=2\times3\times7), (63=3^2\times7), and (105=3\times5\times7). Step 2: The highest powers are (2), (3^2), (5), and (7). Step 3: (2\times9\times5\times7=630), so the LCM is (630).
If (p=2^2\times3^2\times5) and (q=2^3\times3\times5), what is the HCF of (p) and (q)?
Correct answer: B
Step 1: The common prime factors are (2), (3), and (5). Step 2: The smaller powers are (2^2), (3), and (5). Step 3: (4\times3\times5=60), so the HCF is (60).
If (p=2^2\times3^2\times5) and (q=2^3\times3\times5), what is the LCM of (p) and (q)?
Correct answer: C
Step 1: For LCM, take the highest powers of all prime factors. Step 2: The highest powers are (2^3), (3^2), and (5). Step 3: (8\times9\times5=360), so the answer is (360).
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