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If (3x-2, 2x+5, x+16) are consecutive terms of an arithmetic progression, what is the value of (x)?

Answer and explanation

Correct answer: (2)

In three consecutive terms, twice the middle term equals the sum of the other two, so (2(2x+5)=(3x-2)+(x+16)) gives (x=2). The middle-term rule is a fast exam method.

Related tags

ApAlgebraic TermsExpertCommon DifferenceIntroduction To Aps And Common Difference.Introduction To Aps And Common DifferenceArithmetic Progressions (Ap)Arithmetic Progressions Ap

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