In which sequence are the first three consecutive differences (4, 4, 4)?

Correct answer: (2, 6, 10, 14, ...)

The governing concept is the common difference of an arithmetic progression. For option A, subtract consecutive terms: 6−2=4, 10−6=4, and 14−10=4. Thus its first three consecutive differences are exactly (4,4,4), and it is an arithmetic progression with common difference 4. In option B the differences are 4, 5, and 6, so they change. In option C each difference is −2, not +4. In option D the differences are 3, 5, and 7, which also are not constant. Hence only option A satisfies the stated condition. The repeated wording in the supplied option has been normalized, without changing the mathematical choices or answer.