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If (3,m,11) are three consecutive terms of an arithmetic progression, what is (m)?यदि (3,m,11) किसी अंकगणितीय श्रेणी के क्रमागत तीन पद हैं तो (m) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (7)(7)
The middle term is the average of (3) and (11), so (m=\frac{3+11}{2}=7). In three consecutive terms the middle term is the average.बीच का पद (3) और (11) का औसत है इसलिए (m=\frac{3+11}{2}=7)। तीन क्रमागत पदों में मध्य पद औसत होता है।
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