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Find the sum of the first (17) terms of the arithmetic progression (9,15,21,\ldots).समांतर श्रेणी (9,15,21,\ldots) के पहले (17) पदों का योग ज्ञात कीजिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (969)(969)
The seventeenth term is (105), so (S_{17}=\frac{17}{2}(9+105)=969). Finding the last term first makes calculation easier.सत्रहवाँ पद (105) है, इसलिए (S_{17}=\frac{17}{2}(9+105)=969)। पहले अंतिम पद निकालने से गणना आसान होती है।
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