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What is the sum of the first (11) terms of the arithmetic progression (32,28,24,\ldots)?समांतर श्रेणी (32,28,24,\ldots) के पहले (11) पदों का योग क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (132)(132)
The eleventh term is (-8), so (S_{11}=\frac{11}{2}(32-8)=132). The formula remains the same even with a negative last term.ग्यारहवाँ पद (-8) है, इसलिए (S_{11}=\frac{11}{2}(32-8)=132)। ऋणात्मक अंतिम पद होने पर भी सूत्र वही रहता है।
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