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Find the sum of the first (14) terms of the arithmetic progression (60,55,50,\ldots).समांतर श्रेणी (60,55,50,\ldots) के पहले (14) पदों का योग ज्ञात करें।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (385)(385)
The fourteenth term is (-5), so (S_{14}=\frac{14}{2}(60-5)=385). In a decreasing progression, the last term may become negative.चौदहवाँ पद (-5) है, इसलिए (S_{14}=\frac{14}{2}(60-5)=385)। घटती श्रेणी में अंतिम पद ऋणात्मक भी हो सकता है।
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