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What is the sum of the first (11) terms of the arithmetic progression (3,10,17,\ldots)?समांतर श्रेणी (3,10,17,\ldots) के पहले (11) पदों का योग क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (418)(418)
The eleventh term is (73), so (S_{11}=\frac{11}{2}(3+73)=418). Finding the last term correctly is the key step.ग्यारहवाँ पद (73) है, इसलिए (S_{11}=\frac{11}{2}(3+73)=418)। अंतिम पद सही निकालना मुख्य चरण है।
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