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Find the sum of the first (10) terms of the arithmetic progression (40,37,34,\ldots).समांतर श्रेढ़ी (40,37,34,\ldots) के पहले (10) पदों का योग ज्ञात कीजिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (265)(265)
The tenth term is (13), so (S_{10}=\frac{10}{2}(40+13)=265). In a decreasing progression, the last term is smaller.दसवाँ पद (13) है, इसलिए (S_{10}=\frac{10}{2}(40+13)=265)। घटती श्रेढ़ी में अंतिम पद कम होता है।
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