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In an auditorium, the first row has 8 seats and each successive row has 3 more seats than the previous row. If there are 12 such rows, what is the total number of seats?

Answer and explanation

Correct answer: 294

The numbers of seats form an AP, where \(a=8\), \(d=3\), and \(n=12\). Therefore, \(S_{12}=\frac{12}{2}[2(8)+(12-1)3]=6(16+33)=6\times49=294\). Hence, the correct answer is 294. An answer such as 276 does not correctly account for all \(11\) increases up to the last row. Exam tip: in the AP sum formula, the number of common differences is \(n-1\).

Related tags

Arithmetic ProgressionSum Of ApAp Word ProblemClass 10 MathematicsSequence And SeriesFinding The Sum Of The First $N$ Terms Of An ApFinding The Sum Of The First N Terms Of An ApArithmetic Progressions (Ap)

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