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In an auditorium, the first row has 14 chairs and each successive row has 4 more chairs. If there are 9 rows in total, which conclusion is correct?

Answer and explanation

Correct answer: The last row has 46 chairs and there are 270 chairs in total.

This forms an AP with first term \(a=14\), common difference \(d=4\), and \(n=9\) terms. The last row has \(a+(n-1)d=14+8\times4=46\) chairs. Therefore, the total is \(S_9=\frac{9}{2}(14+46)=270\). Option D incorrectly counts 9 common differences; 9 rows have only 8 gaps between them. Exam tip: use \(n-1\) in the formula for the last term.

Related tags

Arithmetic ProgressionSum Of ApNth TermWord ProblemClass 10 MathematicsFinding The Sum Of The First $N$ Terms Of An ApFinding The Sum Of The First N Terms Of An ApArithmetic Progressions (Ap)

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