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What is the sum of the first (16) even natural numbers?

Answer and explanation

Correct answer: 272

The first 16 even natural numbers are 2, 4, 6, ..., 32. They form an AP with \(a=2\), \(d=2\), and \(n=16\). Therefore, \(S_{16}=\frac{16}{2}[2(2)+(16-1)\cdot2]=272\). Hence, 272 is correct. Although 256 equals \(16^2\), the sum of the first 16 even natural numbers is given by \(n(n+1)\). Exam tip: use \(n(n+1)\) directly for the sum of the first \(n\) even natural numbers.

Related tags

Arithmetic ProgressionAp SumEven Natural NumbersSum Of N TermsClass 10 MathematicsFinding The Sum Of The First $N$ Terms Of An ApFinding The Sum Of The First N Terms Of An ApArithmetic Progressions (Ap)

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