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The (9)th term of an arithmetic progression is (46) and the (21)th term is (106). What is the sum of the first (21) terms?

Answer and explanation

Correct answer: 1176

For an AP, \(T_n=a+(n-1)d\). Thus, \(a+8d=46\) and \(a+20d=106\). Subtracting gives \(12d=60\), so \(d=5\) and \(a=6\). Therefore, \(S_{21}=\frac{21}{2}[2a+20d]=\frac{21}{2}[12+100]=1176\). Option 1113 can result from using \(21\times53\), but the average of the first and 21st terms is \(56\), not 53. Exam tip: when two terms are given, form equations first to find \(a\) and \(d\).

Related tags

Arithmetic ProgressionSum Of ApNth TermLinear EquationsClass 10 MathematicsFinding The Sum Of The First $N$ Terms Of An ApFinding The Sum Of The First N Terms Of An ApArithmetic Progressions (Ap)

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