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The first term of an arithmetic progression is (12) and the sum of the first (10) terms is (345). What is the common difference?

Answer and explanation

Correct answer: 5

The sum of the first \(n\) terms of an AP is \(S_n=\frac{n}{2}[2a+(n-1)d]\). Here, \(345=\frac{10}{2}[2(12)+9d]=5(24+9d)\). Thus, \(24+9d=69\), so \(9d=45\) and \(d=5\). If \(d=4\), the sum would be 300, not 345. Exam tip: substitute the given \(a\), \(n\), and \(S_n\) directly into the sum formula to find \(d\).

Related tags

Arithmetic ProgressionAp SumCommon DifferenceLinear EquationsClass 10 MathematicsFinding The Sum Of The First $N$ Terms Of An ApFinding The Sum Of The First N Terms Of An ApArithmetic Progressions (Ap)

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