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Class 10 Mathematics Arithmetic Progressions (AP)Finding the sum of the first $n$ terms of an APExpert

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How many initial terms of the arithmetic progression (81,75,69,\ldots) have sum (315)?

Answer and explanation

Correct answer: (7)

Solving (\frac{n}{2}[162-6(n-1)]=315) gives (n=7). Exam tip: the same sum formula works for decreasing progressions too.

Related tags

Ap Decreasing-Ap Expert Finding The Sum Of The First $N$ Terms Of An Ap Finding The Sum Of The First N Terms Of An Ap Arithmetic Progressions (Ap)Arithmetic Progressions Ap Mathematics

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