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Find the sum of the first (18) terms of the AP (50,47,44,\ldots).

Answer and explanation

Correct answer: (441)

Direct answer: Option A, 441. The AP is 50, 47, 44, and so on. Its first term is a = 50, common difference is d = 47 - 50 = -3, and n = 18. Use the sum formula \\(S_n=\\frac{n}{2}[2a+(n-1)d]\\). Substitution gives \\(S_{18}=\\frac{18}{2}[2(50)+17(-3)]\\) = 9[100 - 51] = 9 × 49 = 441. As a check, the eighteenth term is \\(a_{18}=50+17(-3)=-1\\); the average of the first and last terms is \\((50+(-1))/2=24.5\\), and 18 × 24.5 = 441. Option A is correct. Option B, 459, results from an arithmetic error or mishandling the negative difference. Option C, 468, is not obtained from the correct formula and may come from using an incorrect last term. Option D, 450, is also an incorrect calculation. Common mistake: in a decreasing AP, d must be written as -3, not +3.

Related tags

Decreasing ApAp SumCommon Difference

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