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If (a_n=10n+q) and (a_{7n}-a_{3n}=520), what is the value of (n)?

Answer and explanation

Correct answer: 13

Given \(a_n=10n+q\), we get \(a_{7n}=70n+q\) and \(a_{3n}=30n+q\). Hence, \(a_{7n}-a_{3n}=(70n+q)-(30n+q)=40n\). Therefore, \(40n=520\), so \(n=13\). The constant \(q\) cancels because it occurs in both terms. Exam tip: for terms such as \(a_{7n}\) and \(a_{3n}\), directly substitute \(7n\) and \(3n\) respectively in the term formula.

Related tags

Arithmetic ProgressionsNth TermAlgebraic SubstitutionSequence TermsClass 10 MathematicsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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