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In an arithmetic progression, if a₇ = 36 and a₁₃ = 4a₇ − 12, what is a₃₇?एक अंकगणितीय श्रेणी में, यदि a₇ = 36 और a₁₃ = 4a₇ − 12 है, तो a₃₇ क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 516516
First, a₁₃ = 4(36) − 12 = 132. The terms a₇ and a₁₃ are six positions apart, so 6d = 132 − 36 = 96 and d = 16. Since a₃₇ is 30 positions after a₇, a₃₇ = 36 + 30(16) = 516.पहले, a₁₃ = 4(36) − 12 = 132। a₇ और a₁₃ के बीच छह पदों का अंतर है, इसलिए 6d = 132 − 36 = 96 और d = 16। a₃₇, a₇ से 30 स्थान आगे है; अतः a₃₇ = 36 + 30(16) = 516।
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