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What will be the last term in the AP of positive multiples of (37) less than (3600)?

Answer and explanation

Correct answer: 3589

The sequence of positive multiples is \(37,74,111,\ldots\), whose \(n\)th term is \(37n\). For the last term, \(37n<3600\). Now \(37\times97=3589\), whereas \(37\times98=3626>3600\). Hence, 3589 is the greatest multiple of 37 less than 3600. Although 3626 is the next multiple, it exceeds the given limit. Exam tip: divide by the common difference, take the integer part, and multiply back to find the required multiple.

Related tags

Arithmetic ProgressionNth TermMultiplesFloor ValueClass 10 MathematicsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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