0 reads0 ratings0 helpful
In an arithmetic progression, if a₂₀ = 6a₈ − 13 and a₈ = 37, what is a₃₂?एक अंकगणितीय श्रेणी में, यदि a₂₀ = 6a₈ − 13 और a₈ = 37 है, तो a₃₂ क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 381381
First, a₂₀ = 6(37) − 13 = 209. From a₈ to a₂₀ there are 12 common differences, so 12d = 209 − 37 = 172. From a₂₀ to a₃₂ there are also 12 common differences; hence a₃₂ = 209 + 172 = 381.पहले, a₂₀ = 6(37) − 13 = 209। a₈ से a₂₀ तक 12 सार्व अंतर हैं, इसलिए 12d = 209 − 37 = 172। a₂₀ से a₃₂ तक भी 12 सार्व अंतर हैं; अतः a₃₂ = 209 + 172 = 381।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
