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In an arithmetic progression, if a₁ = 17, d = 10, and a₍₄ₙ₊₃₎ = 397, what is the value of n?एक समांतर श्रेणी में, यदि a₁ = 17, d = 10 और a₍₄ₙ₊₃₎ = 397 है, तो n का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 99
Using aₖ = a₁ + (k − 1)d with k = 4n + 3 gives a₍₄ₙ₊₃₎ = 17 + (4n + 2)10 = 40n + 37. Thus 40n + 37 = 397, so 40n = 360 and n = 9.aₖ = a₁ + (k − 1)d में k = 4n + 3 रखने पर a₍₄ₙ₊₃₎ = 17 + (4n + 2)10 = 40n + 37 मिलता है। इसलिए 40n + 37 = 397, अर्थात 40n = 360 और n = 9।
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