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What is the first term greater than 850 in the AP 27, 40, 53, ...?

Answer and explanation

Correct answer: 859

The first term is a₁ = 27 and the common difference is d = 40 − 27 = 13. Therefore the nth term is aₙ = 27 + (n − 1)13. We need the least n such that this term is strictly greater than 850: 27 + 13(n − 1) > 850. Hence 13(n − 1) > 823, so n − 1 > 63.307..., and the least integer value is n − 1 = 64, or n = 65. The term is a₆₅ = 27 + 64 × 13 = 27 + 832 = 859. The preceding term is a₆₄ = 27 + 63 × 13 = 846, which is not greater than 850. Thus option B is the first qualifying term. Options C and D are later terms, while A fails the strict inequality.

Related tags

Arithmetic ProgressionNth TermInequalityFirst Greater TermFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)Arithmetic Progressions Ap

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