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If (a_n=7n+c) and (a_6=61), what is (r) when (a_{4r}=299)?

Answer and explanation

Correct answer: 10

Given \(a_n=7n+c\). Substituting \(n=6\), \(a_6=42+c=61\), so \(c=19\). Now \(a_{4r}=7(4r)+19=28r+19\). From \(28r+19=299\), we get \(28r=280\), hence \(r=10\). If 9 were used, the term would be 271, not 299. Exam tip: first find the constant \(c\) from the given term, then substitute the required index in the formula.

Related tags

Arithmetic ProgressionNth TermLinear SequenceAlgebraGrade 10Finding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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