In an arithmetic progression, if a₅ = 31 and a₁₂ + a₁₉ = 242, what is a₃₃?एक समांतर श्रेणी में, यदि a₅ = 31 और a₁₂ + a₁₉ = 242 है, तो a₃₃ क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 271271
Using aₙ = a₅ + (n − 5)d, we get a₁₂ + a₁₉ = (31 + 7d) + (31 + 14d) = 242. Hence 21d = 180, so d = 60/7. Therefore, a₃₃ = 31 + 28(60/7) = 271.aₙ = a₅ + (n − 5)d का उपयोग करने पर a₁₂ + a₁₉ = (31 + 7d) + (31 + 14d) = 242 मिलता है। इसलिए 21d = 180 और d = 60/7। अतः a₃₃ = 31 + 28(60/7) = 271।
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