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In the AP (42,55,68,\ldots), how many terms are less than (1000)?

Answer and explanation

Correct answer: 74

Here, the first term is \(a=42\) and the common difference is \(d=13\). The \(n\)th term is \(a_n=42+13(n-1)\). From \(42+13(n-1)<1000\), we get \(13n<971\), so \(n<74.69\). Hence, there are \(74\) terms less than 1000. The \(75\)th term is \(1017\), which is not less than 1000. Exam tip: after solving an inequality for the number of terms, take the greatest integer satisfying it.

Related tags

Arithmetic ProgressionNth TermInequalitiesCounting TermsClass 10 MathematicsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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