In an arithmetic progression, if a₆ = 28 and a₁₁ = 3a₆ + 6, what is a₃₁?एक समांतर श्रेणी में, यदि a₆ = 28 और a₁₁ = 3a₆ + 6 है, तो a₃₁ क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 338338
First, a₁₁ = 3(28) + 6 = 90. From a₆ to a₁₁ there are 5 equal steps, so 5d = 90 − 28 = 62. Thus a₃₁ = a₆ + 25d = 28 + 25(62/5) = 338.पहले, a₁₁ = 3(28) + 6 = 90। a₆ से a₁₁ तक 5 समान अंतर हैं, इसलिए 5d = 90 − 28 = 62। अतः a₃₁ = a₆ + 25d = 28 + 25(62/5) = 338।
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