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In an arithmetic progression, a₈ = 37 and a₁₂ = 2a₈ + 22. What is a₂₈?एक समान्तर श्रेणी में a₈ = 37 और a₁₂ = 2a₈ + 22 है। a₂₈ का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 332332
First, a₁₂ = 2(37) + 22 = 96. The common difference is d = (96 − 37)/(12 − 8) = 59/4. Thus, a₂₈ = a₈ + 20d = 37 + 20(59/4) = 332.पहले, a₁₂ = 2(37) + 22 = 96। सार्व अंतर d = (96 − 37)/(12 − 8) = 59/4 है। इसलिए a₂₈ = a₈ + 20d = 37 + 20(59/4) = 332।
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