In an AP, a_10 = 4a_4 + 6 and a_4 = 14. What is a_22?एक समान्तर श्रेणी (AP) में a_10 = 4a_4 + 6 और a_4 = 14 है। a_22 का मान क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 158158
First, a_10 = 4 × 14 + 6 = 62. The 10th and 4th terms are six positions apart, so 62 − 14 = 6d, giving d = 8. Thus a_22 = a_10 + 12d = 62 + 12 × 8 = 158.पहले, a_10 = 4 × 14 + 6 = 62। 10वाँ और 4था पद छह स्थान दूर हैं, इसलिए 62 − 14 = 6d और d = 8। अतः a_22 = a_10 + 12d = 62 + 12 × 8 = 158।
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