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In an AP, a_6 = 23 and a_18 = 95. Find a_33.एक समान्तर श्रेणी (AP) में a_6 = 23 और a_18 = 95 है। a_33 ज्ञात कीजिए।
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: 185185
The common difference is d = (95 − 23)/(18 − 6) = 72/12 = 6. From the 18th term to the 33rd term there are 15 steps, so a_33 = 95 + 15 × 6 = 185.सार्व अंतर d = (95 − 23)/(18 − 6) = 72/12 = 6 है। 18वें पद से 33वें पद तक 15 कदम हैं, इसलिए a_33 = 95 + 15 × 6 = 185।
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