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What is the last term in the AP of positive multiples of (23) less than (2000)?

Answer and explanation

Correct answer: 1978

The sequence of positive multiples is \(23, 46, 69, \ldots\), and its \(n\)th term is \(23n\). For the last term, \(23n<2000\). Since \(2000\div23\approx86.95\), the greatest integer value of \(n\) is 86. Thus, the last term is \(23\times86=1978\). Although \(2001=23\times87\), it is greater than 2000. Exam tip: for “less than” questions, check that the next multiple does not cross the given limit.

Related tags

Arithmetic ProgressionPositive MultiplesNth TermInequalitiesClass 10 MathematicsFinding The $N$Th Term Of An ApFinding The N Th Term Of An ApArithmetic Progressions (Ap)

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